Question

please help me to do the practice zone-2 of maths ch name- exponents and powers​

Answer 1

Answer:

$=> {9}^{2p - 1} \div 81 = 9 \\ = > \frac{{9}^{2p - 1}}{81} = 9 \\ = > \frac{{9}^{2p - 1}}{ {9}^{2} } = 9 \\ => {9}^{2p - 1} = 9 \times {9}^{2} \\ = > {9}^{2p - 1} = {9}^{3} \\ = > 2p - 1 = 3 \\ = > 2p = 4 \\ = > p = 2$