Question

please help me to do this please please please please please please​

Answer 1

Step-by-step explanation:

Given: ABCD is a parallelogram. P is the midpoint of CD.

Also, Q is a point on AC such that CQ = (1/14) * AC  and PQ produced meet BC in R.

Therefore OC = (1/2) AC

⇒ OQ = OC-CQ

          = (1/2)AC - (1/4)AC

         = (1/4)AC.

Also, OQ = CQ

Therefore Q is the midpoint of OC.

In triangle OCD,

P is the midpoint of CD and Q is the midpoint of OC,

therefore PQ is parallel to OD (Midpoint theorem)

⇒ PR is parallel to BD

In triangle BCD,

P is the midpoint of CD and PR is parallel to BD,

By Converse of midpoint theorem

Therefore, R is the midpoint of BC.

Hope it helps!