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Answers
Question :-
A 8000 kg engine pulls a train of 5 wagons , each of 2000 kg along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate :
(a) the net accelerating force;
(b) the acceleration of the train , and
(c) the force of wagon 1 on wagon 2.
Answer :-
(a) Net accelerating force
Force exerted by the wagon = 40,000 N
Frictional force = 5,000 N
∴ Net accelerating force = 40,000 N - 5,000 N
= 35,000 N
The net accelerating force is 35,000 N
(b) Force = mass × acceleration
==> acceleration = force / mass
Given :
force exerted = 35,000 N
mass of the train
mass of engine = 8,000 kg
mass of a wagon = 2,000 kg
mass of 5 wagons = 2,000 × 5 kg
= 10,000 kg
mass of the whole train = 10,000 kg + 8,000 kg
= 18,000 kg
acceleration
So acceleration = force / mass
= 35,000 N / 18,000 kg
= 35 / 18 m/s²
= 1.9444.... m/s²
The acceleration was 1.94 m / s²
(c) Force of wagon 1 on wagon 2
Consider only 4 wagons here because 4 are exerting pressure on the first....
Accelerating force = mass × acceleration
mass = 2,000 kg × 4 = 8,000 kg
force = 8,000 kg × 1.94 m/s²
= 155200 N
The force will be 1,55,200 N
Hope it helps !