Question

please help me to find angle DCE

Answer 1

In triangle ABD ,
angle A= 90  (given)
ANGLE abd +angle bda +90 =180 .......asp
         y  + x = 180-90= 90 
 
now, x:y= 11:19
        11m + 19m =90
          m =  90/30 = 3
   
x =11m =11*3 =33
y =19m =19*3 =57

now, ad ll bc and bd is the transversal.
      x= angle dbc
       angle dbc= 33
  
   angle dbc  +  angle bdc  = angle DCE
     
     angle DCE = 33+32
                       = 65 degree.....
        

Answer 2

Hope it is helpful to uh..