Question

please help me to find cube
(2x+3y)

Answer 1

Given that : (2x+3y)

We have to find the cube of (2x+3y)

As we know that :

${(a + b)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3}$

Now, according to the question :

${(2x + 3y)}^{3} = {(2x)}^{3} + 3 {(2x)}^{2} (3y) + 3(2x) {(3y)}^{2} + {(3y)}^{3} \\ \\ = > {(2x + 3y)}^{3} = 8 {x}^{3} + 36 {x}^{2} y + 54x {y}^{2} + 27 {y}^{3}$