Question

Please help me to find the answer for this qn....​

Answer 1

Step-by-step explanation:

In ΔACQ

AQ² = AC² + QC²

AQ² = AC² + (BC/2)²

AQ² = AC² + BC²/4    .............(1)

In ΔBPC

BP² = BC² + PC²

BP² = BC² + (AC/2)²

BP² = BC² + AC²/4        ...........(2)

Adding (1) and (2)

AQ² + BP² = AC² + BC² + AC²/4 + BC²/4 

4(AQ² + BP²) = 5AC² + 5BC²  

4(AQ² + BP²) = 5(AC² + BC²)

4(AQ² + BP²) = 5(AB²)