Question

please help me to find the value of x
$\binom{2}{x} + x - \sqrt[5]{x} = 3 \times \frac{ {x}^{2} }{n}$
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Answer 1

Answer:

Let, f(x)=mx3+x2 −2x+n

Since (x+1) is a factor of f(x),  

then f(−1)=0

⇒−m+1+2+n=0

⇒m−n=3...(1)

Since (x−1) is a factor of f(x),

then f(1)=0

⇒m+1−2+n=0

⇒m+n=1...(2)

Solving from (1) and (2) we get m=2 and n=−1

Answer 2

Answer:

( x^2 ) + x− 5

x = 3× n

x^2.

$thanks$