please help me to get this answer plzzzz
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here B=90-A
√tanAcotA+tan^2A/sinAcosecA -cos^2A/cos^2A
=√1+tan^2A-1
=√tan^2A
=tanA
√tanAcotA+tan^2A/sinAcosecA -cos^2A/cos^2A
=√1+tan^2A-1
=√tan^2A
=tanA
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