Please help me to prove this question
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sin3A = 3 sinA - 4 sin^3A
cos3A= 4 cos^3A- 3 cosA
substitute this in the problem....we get....
= (3sin A - 4sin^3A + sinA) sinA + (4cos^3A - 3cosA-cosA)cosA
= (4sinA - 4 sin^3A) sin A + (4cos^3A - 4cosA) cosA
common 4sinA
= (1-sin^2A) 4sin^2A - (1-cos2A) 4cos2A
1-sin^2A = cos^2A
1-cos^2A = sin^2A
= 4 sin^2A cos^2A - 4cos^2A sin^2A
= 0(proved)
hope it helps you......mark this answer as brailiest if it really helped you and liked my work.
cos3A= 4 cos^3A- 3 cosA
substitute this in the problem....we get....
= (3sin A - 4sin^3A + sinA) sinA + (4cos^3A - 3cosA-cosA)cosA
= (4sinA - 4 sin^3A) sin A + (4cos^3A - 4cosA) cosA
common 4sinA
= (1-sin^2A) 4sin^2A - (1-cos2A) 4cos2A
1-sin^2A = cos^2A
1-cos^2A = sin^2A
= 4 sin^2A cos^2A - 4cos^2A sin^2A
= 0(proved)
hope it helps you......mark this answer as brailiest if it really helped you and liked my work.
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