Math, asked by MNSD, 3 months ago

please help me to solve​

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Answered by naitikshaw2007
0

Answer:

Ahh simple

by last line of question ...we can understand it's asking area

so taking out area of 2(lb + bh + hl)

2 x ( 5O x 3O) + (3O x 4O) + (4O x 5O)

2 x 47OO

94OO cm²

In metre = 94OO\1OO is 94m²

Required = cost of such 2O tins is

2O rupees \m²

2O x 94 is 188 rupees

NOW 2O such required tin

So 188 x 2O is 376O rupees

Your answer in wrong (367)

It will be 367O

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