please help me to solve
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Ahh simple
by last line of question ...we can understand it's asking area
so taking out area of 2(lb + bh + hl)
2 x ( 5O x 3O) + (3O x 4O) + (4O x 5O)
2 x 47OO
94OO cm²
In metre = 94OO\1OO is 94m²
Required = cost of such 2O tins is
2O rupees \m²
2O x 94 is 188 rupees
NOW 2O such required tin
So 188 x 2O is 376O rupees
Your answer in wrong (367)
It will be 367O
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