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Answers
Step-by-step explanation:
firstly, change the sign of the denominator , i.e √7 - √2 will become √7 + 2 , so multiply this term both with numerator and denominator.
= 1(√7/2)÷(√7+2)(√7-2)
Multiply the terms , and we know that (a+b)(a-b) = a² - b² , use this identity for denominator!
= √7+2/√(7²) - (2)²
solve it more , square root and square will cancel out!
= √7+2/7-4
= √7+2/3
thus , after rationalising we will get :-
√7+2/3
2.
Given polynomial p(x) = ax + b.
This is a linear polynomial. So it has unique solution.
Now, Let's see if -b/a would be a zero of the polynomial.
ax + b = 0
ax = -b
x = -b/a
As we know the value of the variable for which polynomial would be zero is known as zero of the polynomial. Therefore, For -b/a the given polynomial is 0
Therefore, You can conclude that -b/a is the zero of the linear polynomial ax+b.
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