Math, asked by poojakumaresh26, 1 year ago

please help me to solve from this step.... coordinate geometry

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Answered by TPS
1
See, under the root, there are two terms:

first \: term : \: {a}^{2} ( {y - x})^{2} (y + x)^{2} \\ second \: term : \: 4{a}^{2} ( {y - x})^{2}

What is common between the two terms?

Common between two terms are a^2 and (y-x)^2

So if you take them common,
in the first term, (y+x)^2 will remain
in the second term, 4 will remain

So after taking common, it will be

( {a}^{2} ) \times {(y - x)}^{2} \times [(y + x)^{2} + 4]

So AB will be

AB = \sqrt{( {a}^{2} ) \times {(y - x)}^{2} \times [(y + x)^{2} + 4]} \\ \\ AB = a \times (y - x) \times \sqrt{(y + x)^{2} + 4}

 AB = a (y - x) \sqrt{(y + x)^{2} + 4}
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