Question

Please help me to solve it !!

Answer 1

hey mate here is ur ans
before that u must know trigonometry table values
tan 60= root 3
tan 30= 1/root 3

so
tan(a+b)=root 3
=>tan(a+b)=tan 60
so a+b=60--------1

now again
tan (a-b) =1/root 3
tan(a-b) =tan 30
so a-b=30-------2

solve equations one and two
a+b=60
a-b=30
------------
2a=90
a=90/2=45

so b = 60-a=60-45=15

thus a is 45 degrees and b is 15 degrees

Answer 2

tan ( A + B ) = √3

→ A + B = 60° { tan 60° = √3 } .... ( i )

tan ( A - B ) = 1/√3

→ A - B = 30° { tan 30° = 1/√3 } .... ( 2 )

Solving ( i ) and ( 2 )

A + B = 60°

+A - B = 30° / 2A = 90°

→ A = 45°

45° + B = 60°

:- B = 60° - 45° = 15°

Thus , A = 45° and B = 15°