Physics, asked by Nidhibhanushali, 10 months ago

please help me to solve it
The length of min-hand of a clock is 14cm. Calculate the speed at which the tip of minute-hand moves.

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Answered by Anonymous
15

HeRe Is Your Ans

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Given :-

R = 14 cm

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Tip of minute clock travel's distance = circumference of circle of radius 14 cm in 60 minutes ( 3600 seconds )

 =  > speed =  \frac{2 \times 3.14 \times 14}{3600}  \\  \\  =  > speed  =  \frac{87.92}{3600}  \\  \\  =  > 0.0244 \:  \:  \:  \frac{cm}{sec}

 \fbox{ans = 0.0244 \:  \:  \frac{cm}{sec} }

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 <marquee > hope it helps u

Answered by siddhartharao77
5

Answer:

0.024 cm/s

Explanation:

Minute-hand of a clock describes a circle of radius equal to its length = 14 cm.

Therefore, radius = 14 cm.

∴ Distance = 2πr

                  = 2 * (22/7) * 14

                  = 88 cm

The time it takes to complete one full revolution by seconds hand = 3600 seconds.

Speed = Distance/Time

          = 88/3600

          = 0.024 cm/s

Therefore, Speed is 0.024 cm/second.

Hope it helps!

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