Math, asked by Ronakmangal189, 3 months ago

Please help Me to solve my query​

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Answered by gorachandhansda405
1

Step-by-step explanation:

  • (a^x+1 /a^y+1)^x+y * (a^y+2/a^z+2)^y+z * (a^z+3/a^x+3 ) ^z+x = 1
  • {a^(x+1)-(y+1)}^x+y *{a^(y+2)-(z+2)}^y+z *{a^(z+3)-(x+3)}^z+x =1
  • {a^(x+1-y-1) }^x+y *{a^(y+2-z-2)}^y+z *{a^(z+3-x-3)}^z+x = 1
  • a^(x-y)(x+y)*a^(y-z)(y+z)*a^(z-x)(z+x)=1
  • a^(x^2-y^2 )*a^(y^2-z^2) *a^(z^2-x^2)= 1
  • a^(x^2-y^2)+(y^2-z^2)+(z^2-x^2 ) = 1
  • a^(x^2-y^2+y^2-z^2+z^2-x^2) = 1
  • a^0 = 1
  • 1 = 1
  • Hence, proved.
Answered by Anonymous
2

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