Question

Please help me to solve question no. 10

Answer 1

Since the two end points are at the diameter, the wire is equally divided into two parts, both of 10 ohms.
These two parts are in a parallel circuit.
Let R be the equaivalent resistance. Therefore:-
1/R = 1/10 + 1/10
1/R = 1/5
R = 5 ohms
Hence the effective rwsistance between tqo points at the ends of any diameter of the circle is 5 ohms

Answer 2

Hey there !!!

A 20ohm wire is bent into a circle with two resistors at the ends of diameter of the circle and resistances of these 2 resistors will be 20/2=10ohms each and they are in parallel connection.

So, equivalent resistance 1/R=1/R₁+1/R₂= 1/10+1/10=2/10=1/5

                                               1/R=1/5

                                      R=5 ohms

Hope this helped you ..............