Question

please help me to solve the above sum.​

Answer 1

Answer:

3/5

Step-by-step explanation:

A(∆ABD)/A(∆ABC)= [1*(AP)(BD)/2]/[1*(AP)(BC)/2]

=BD/BC= 3/5

Answer 2

Answer:

$\huge\fbox \red{A}\fbox \green{n}\fbox \purple{s}\fbox \orange{w}\fbox \red{e}\fbox \color{aqua}{r}$

$area \: of \: triangle = \frac{1}{2} \times base \times hight \\ base \: of \triangle \: abd = bd = 3 \\ base \: of \triangle \: abc = bc = 5 \\ \frac{area \triangle \: abd}{area \triangle \: abc} = \frac{ \frac{1}{2} \times 3 \times ap}{ \frac{1}{2} \times 5 \times ap } \\ \huge{\looparrowright} \frac{3}{5} \\ \\ here \: is \: your \: answer \: plese \: mark \: brillant \: plese.$