Please help me to solve the Q. No. 23.
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h=300m
From point A, angle is 30°
tan30°=300/Base1
Base1=300 ×root3 m
At B, angle=45°
tan45°=300/base2
base2=300m
Then, width = base 1 + base 2= 300 (root3 + 1)m
From point A, angle is 30°
tan30°=300/Base1
Base1=300 ×root3 m
At B, angle=45°
tan45°=300/base2
base2=300m
Then, width = base 1 + base 2= 300 (root3 + 1)m
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