please help me to solve these questions
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3) let angle AOC= 5x and angle COB= 4x
thus, angle AOD = 4x, angle DOB=5x (V.O.A)
angle AOC+ angle COB= 180 degrees
thus, 5x + 4x = 180
9x= 180
x= 180/9
20=x
{Thus, angle AOC= 5*20=100 = angle DOB
angle COB = 4*20 = 80 = angle AOD } ans.
shiva8745:
it's correct
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Hola!!
Here's your answer :-
In the given figure
Let, angle AOC = 5x & angle BOC = 4x
So, ang. AOC+ BOC = 180° (☆ linear pair )
=> 5x + 4x = 180°
=> 9x = 180°
=> x = 180°/9
=> x = 20°
ang. AOC = 5x = 5 × 20° = 100°
ang. BOC = 4x = 4 × 20° = 80°
ang. BOD = 100° (☆Vertically opposite ang.)
ang. AOD = 80° (☆Vertically opposite ang.)
Hope it helps you
Here's your answer :-
In the given figure
Let, angle AOC = 5x & angle BOC = 4x
So, ang. AOC+ BOC = 180° (☆ linear pair )
=> 5x + 4x = 180°
=> 9x = 180°
=> x = 180°/9
=> x = 20°
ang. AOC = 5x = 5 × 20° = 100°
ang. BOC = 4x = 4 × 20° = 80°
ang. BOD = 100° (☆Vertically opposite ang.)
ang. AOD = 80° (☆Vertically opposite ang.)
Hope it helps you
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