Question

please help me to solve these questions please​

Answer 1

Answer:

grc-pncm-muq

not for bad..

Answer 2

Answer:

In ΔACE ,

    62° + 43° + ∠AEC = 180°

   => ∠AEC = 75°   (i)

Now, AEDB is an cyclic quadrilateral ,

      62° +  180° - c  = 180°     ( two opposite angles ar 180° )

=> c =  62°

Now, a + ∠AED = 180°

     => a + 75° = 180°     [ from (i) ]

     => a = 105°    (ii)  

Now, in ΔABF ,

       62° + a + b = 180°

    => 62° + 105° + b = 180°    [from eq (II) ]

    => b = 13°

∴ a = 105° , b = 13° and c = 62°   (Ans.)

                                                 Thank U

                                        Stay home Stay safe