Physics, asked by dodo757, 6 hours ago

Please help me to solve this

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Answered by Hippocrate
1

(c) 2n-1/2n+1

 \bf\huge\underline{\underline{ Given :- }}

  • Distance =   \bf S_{n}

  • time , t¹ = n - 1

  • time , t² = n

 \bf\huge\underline{\underline{ To \: Find:- }}

  • \bf  \frac{S_{n} }{S_{n}+1} \\

 \bf\huge\underline{\underline{ Answer :- }}

  • t¹ = n - 1

  • t² = n

  • ∆t = t² - t¹

  •   \red{\implies} ∆t = n - n - 1

 \rule{10cm}{0.0005cm}

  •  \boxed{\bf\red{ s = ut + \frac{1}{2} at²}} \\

  •  \bf S_{n} = 0[n-n-1] + \frac{1}{2} a[n² - (n-1)²] \\

  •  \bf S_{n} = \frac{a}{2}(n² - (n² + 1 - 2n  ) \\

  •  \bf S_{n} = \frac{a}{2}(n² - n² - 1  + 2n  ) \\

  •  \bf S_{n} = \frac{a}{2} ( 2n -1  ) \\

 \rule{10cm}{0.0005cm}

  •  \bf S_{n+1} = 0[n+1 -n] + \frac{1}{2} a[(n+ 1)²-n²] \\

  •  \bf S_{n+1} = \frac{1}{2} a[n²+ 1+2n-n²] \\

  •  \bf S_{n+1} = \frac{a}{2} (2n+ 1) \\

 \rule{10cm}{0.0005cm}

  • \bf  \frac{S_{n} }{S_{n}+1} \\

  •   \bf\red{\implies} \frac{\frac{a}{2}(2n-1)}{\frac{a}{2}(2n+1)} \\

  •   \bf\red{\implies} \frac{2n-1}{2n+1} \\

 \rule{10cm}{0.05cm}

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