Math, asked by pappuguptas0055, 11 days ago

please help me to solve this​

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Answered by Anonymous
8

Given :-

p = - 2 , q = - 1 & r = 3

To Find :-

Value of p² + q² - r³

Solution :-

To solve this question just simply put all the known values ;

 { \quad \qquad { \tt \leadsto p² + q² - r³ }}

 { : \implies \quad { \sf ( - 2 )² + ( - 1 )² - ( 3 )³ }}

 { : \implies \quad { \sf \{ - 2 × - 2 \} + \{ - 1 × - 1 \} - \{ 3 × 3 × 3 \} }}

 { : \implies \quad { \sf \{ \cancel{-} 2 × \cancel{-} 2 \} + \{ \cancel{-} 1 × \cancel{-} 1 \} - \{ 3 × 3 × 3 \} }}

 { : \implies \quad { \sf \{ 2 × 2 \} + \{ 1 × 1 \} - \{ 27 \} }}

 { : \implies \quad { \sf \{ 4 \} + \{ 1 \} - \{ 27 \} }}

 { : \implies \quad { \sf 4 + 1 - 27 }}

 { : \implies \quad { \sf 5 - 27 }}

 { : \implies \quad { \bf - 22 }}

Henceforth , The Required Answer is " - 22 " !

Answered by sradhadileep191sa49
0

Answer:

-22

Step-by-step explanation:

p = -2

q = -1

r = 3

p² + q² - r³

= (-2)² + (-1)² - (3)³

= 4 + 1 - 27

= 5 - 27

= -22

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