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Answer:
Step-by-step explanation:
=> x² + y² + 2xy = 9xy .. .. .. // add 2xy both sides
=> (x + y)² / 3² = xy
=> {(x + y) / 3}² = xy
take log both sides
2 log {(x + y) / 3} = log (xy) = log x + log y
log {(x + y) / 3} = (log x + log y) / 2
x^2+y^2=7xy, then log1/3(x+y)= _____
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Answer:
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Step-by-step explanation:
x^2+y^2=7xy, then log1/3(x+y)= ____
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