Question

Please help me to solve this.... Don't spoil​

Answer 1

Answer:

(k+4)X2+(k+1)x+1=0

so, above quadratic equation has equal roots,

.. D=0=(k+1)²_4(k+4).1 =0

===>k²+2k +1_4k_16=0==>k²-2k-15=0

===>(k+3)(k-5)=0. =>k= -3,5

Step-by-step explanation:

when kk=-3,then equation (1) becomes

x²-2x+1=0. =>. (x-1)²=0. x=1,1

when k=5,then equation 2becomes

9x²+6x+1=0. =>(3x+1)²=0. =>x=-1/3,-1/3

hence roots are 1,1and -1/3,-1/3

hope this will help you

Answer 2

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