Question

Please help me to solve this problem. ​

Answer 1

Answer:

answer in attachment

Answer 2

To find:

Length of a seconds pendulum.

Calculation:

The time period offer seconds' pendulum is 2 seconds.

General expression for time period of pendulum is as follows:

$\boxed{ \rm{T = 2\pi \sqrt{ \dfrac{l}{g} } }}$

Here l is the length of pendulum and g is the acceleration due to gravity at that point.

Putting available values:

$= > \rm{T = 2\pi \sqrt{ \dfrac{l}{g} } }$

$= > \rm{2 = 2\pi \sqrt{ \dfrac{l}{9.8} } }$

$= > \rm{ \dfrac{1}{\pi} = \sqrt{ \dfrac{l}{9.8} } }$

$= > \rm{ \dfrac{l}{9.8} = \dfrac{1}{ {(\pi)}^{2} } }$

$= > \rm{ l = \dfrac{9.8}{ {(\pi)}^{2} } }$

$= > \rm{ l = 0.992 \: m}$

So, final answer is:

$\boxed{\rm{ length \: of \: pendulum = 0.992 \: m}}$