Please help me to solve this ques...!!!!
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so simple...
in triangle ABD,
DA+BA>BD ......(1) (SUM OF ANY TWO SIDES IS FREATER THAN 3RD SIDE)
but BA = AC .... (2)
and DA+AC=CD .... (3)
so, replacing eq. (2) with eq.1 we get
DA+AC > BD
and from eq.3 we have
CD > BD.
hence, proved
in triangle ABD,
DA+BA>BD ......(1) (SUM OF ANY TWO SIDES IS FREATER THAN 3RD SIDE)
but BA = AC .... (2)
and DA+AC=CD .... (3)
so, replacing eq. (2) with eq.1 we get
DA+AC > BD
and from eq.3 we have
CD > BD.
hence, proved
galaxygrand0828:
thanks soo much
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