Question

please help me to solve this question​

Answer 1

Answer:

Explanation:

SIDE OF THE FIELD = 10 M

TIME TAKEN TO COVER ONE ROUND 40 SEC

TIME GIVEN =  2 MIN  20 SEC

                    =   2*60+20

                    =  120+20

WHICH CAN BE WRITTEN AS = 40+40+40+20   [ SPLITTING 120 SEC]

                                                   = 40*3+20

THERE FORE THE MAN COVERS 3 ROUNDS AROUND HIS FIELD IN THE FIRST 120 SEC

GIVEN ,

10*4 [ BOUNDARY OF THE FIELD] TAKES 40 SEC

40 M COVERED IN 40 SEC.

THEREFORE DISTANCE COVERED IN 20 SEC= 20*40/40

                                                                             = 20 M

THE  IS THE FARMER  REACHES THE OPPOSITE CORNER OF THE SQUARE FIELD STARTING FROM  ONE CORNER.

THEREFORE DISPLACEMENT IN 20 SEC= DIAGONAL OF THE SQUARE

    = √2 * A [ SIDE OF THE SQUARE].

    = √2 * 10

    = 10√2

    = 10*1.4

    = 14 M.

HOPE THIS HELPS.