Question

please help me..to solve this question.............​

Answer 1

$\bf{ \underline{ \underline{Question}}}$

• The difference of squares of two natural number is 88. If the larger number is 5 less then the the twice of smaller number. Then find the numbers

$\bf{ \underline{ \underline{Answer}}}$

• 93 , 31

• 181 , 57

$\bf{ \underline{ \underline{Solution}}}$

$\sf{Let\:one\:number\:=\:x}$

$\sf{So\:another\:number\:=\:2x-5}$

$\bf{A.T.Q}$

$\mapsto\sf{ \ (2x-5)^{2}-\ x^{2}\:=\:88}$

$\mapsto\sf{4\ x^{2}+25-20x-\ x^{2}\:=\:88}$

$\mapsto\sf{3\ x^{2}-20x+25\:=\:88}$

$\mapsto\sf{3\ x^{2}-15x-5x+25\:=\:88}$

$\mapsto\sf{3x(x-5)-5(x-5)\:=\:88}$

$\mapsto\sf{(x-5)(3x-5)\:=\:88}$

$\bf{ \underline{ \underline{One\:Number}}}$

$\sf{x\:=\:93}$

$\sf{x\:=\:31}$

$\bf{ \underline{ \underline{Another\: Number}}}$

$\sf{x\:=\:181}$

$\sf{x\:=\:57}$

$\huge\sf{Numbers }$

$\sf{ \boxed{93,181}}$

$\sf{ \boxed{31,57}}$

Answer 2

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