Question

please help me to solve this question

Answer 1

Let first number be a

Second number = a+1

Third number = a+2


According to question

=> 3(a+2)+ 4(a+1) + 5(a) = 226

=> 3a + 6 + 4a +4 + 5a = 226

=> 12a + 10 = 226

=> 12a = 216

=> a = 18


First number = 18

Second number = 19

Third number = 20