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Resistance of each resistor R=9Ω
Two resistor connected across A and B are connected in parallel.
Equivalent resistance across A and B
Rab= R×R/R+R= R/2 = 9/2 =4.5 ohm
This equivalent resistance is connected in series to another resistor R.
So equivalent resistance across A and C
Rac=Rab+R=4.5+9=13.5Ω
(ii) Two resistors in series and one in Parallel R=R1+R2=9+9=18Ω
1/R'=1/R+1/R0=1/18+1/9=1+2/18=3/18
R'=18/3=6Ω
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