Question

please help me to solve this question

Answer 1

Hey........!!! Here is ur answer..........☺️☺️☺️

Here........... Given that,

tanA = 5/6 and tanB = 1/11

We know that....

tan(A+B) = (tanA+tanB)/1–tanAtanB

then,

=>tan(A+B) = (5/6+1/11)/1–5/6×1/11

=>tan(A+B) = [(55+6)/66]/1–5/66

=>tan(A+B) = (61/66)/[(66–5)/66]

=>tan(A+B) = (61/66)/(61/66)

=>tan(A+B) = 1

=>A+B = tan–1(1)

=>A+B = 45°

Here we use A and B in place of thetha and phie.I hope u can understand.

I hope it will help u.........✌️✌️✌️

Answer 2

Hi ,

I'm using A , B as angles .

It is given that ,

tan A = 5/6 ,

tan B = 1/11 ,

Now ,

tan ( A + B )

= ( tan A + tan B )/ ( 1 - tanA tanB )

= ( 5/6 + 1/11 ) / [ 1 - ( 5/6 )(1/11 ) ]

= [( 55 + 6 )/66 ]/[ ( 66 - 5 )/66 ]

= 61/61

= 1

tan ( A + B ) = 1

Tan ( A + B ) = tan π/4

A + B = π/4 = 46°

I hope this helps you.

: )