Question

Please help me to solve this question​

Answer 1

Answer:

(i) (3x²)^0= 1

(because If the power on a number is zero, then its value is always zero.)

(ii) (xy)^-2= 1/(xy)²

(iii) (-27a^9)^2/3

$( - 27 {a}^{9} )^{ \frac{2}{3} } = ( - {3}^{3} )^{ \frac{2}{3} } .( {a}^{9} ) ^{ \frac{2}{3} } = ( - 3)^{2}.( {a}^{3})^{2} = 9. {a}^{6}$

this is Ans of (iii) part