Please Help me to solve this question it came in 9th final exams (CBSE)
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For expansion you will take the first term as a and second as b.So,the formula is
(a^3-b^3)=a^3-b^3-3*a*b(a-b)
So now put 1/x in a’s position and y/3 in b’s position
Hope this helps
(a^3-b^3)=a^3-b^3-3*a*b(a-b)
So now put 1/x in a’s position and y/3 in b’s position
Hope this helps
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