Question

please help me to solve this question of chemistry​

Answer 1

Answer:

Al2O3

1 mole of Al2O3 =formula mass of Al2O3 in grams =Mass of Al ×2+Mass of O×3=27×2+16×3=54+48=102 grams

1 mole of Al2O3 contains 2 molecules of Al

1 mole of Al2O3 =6.02×10^23=102g

Then , 2×102×10^23

0.051g of Al2O3

1 gram of Al2O3 =2×6.02×10^23/102×0.051

=6.02×10^20

=1/6.02×10^23×6.02×10^20

=10^20/10^20×103

=0.001 mole

I hope it's help you sister good evening