please help me to solve this questions .
By making Quadratic equations
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1
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3 - Let, two required numbers be x and y.
here, x+y = 27. ...(1)
x×y = 182
or, x (27-x) = 182
or, x^2-27x+182 = 0
or, x^2-14x-13x+182 = 0
or, x(x-14)-13(x-14) =0
or, (x-14) (x-13) =0
or, x= 14 or 13
Hence, Required numbers are 13 and 14...
4 - Let the two consecutive numbers be x and x+1
A/Q
x^2+(x+1)^2 = 365
Now, solve it and find out answer...
Answered by
9
Answer:
365
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