Math, asked by 34priyanshutiwari, 8 months ago

please help me to solve this questions .
By making Quadratic equations​

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Answered by Anonymous
1

Answer:

3 - Let, two required numbers be x and y.

here, x+y = 27. ...(1)

y = 182

or, x (27-x) = 182

or, x^2-27x+182 = 0

or, x^2-14x-13x+182 = 0

or, x(x-14)-13(x-14) =0

or, (x-14) (x-13) =0

or, x= 14 or 13

Hence, Required numbers are 13 and 14...

4 - Let the two consecutive numbers be x and x+1

A/Q

x^2+(x+1)^2 = 365

Now, solve it and find out answer...

Answered by Anonymous
9

Answer:

365

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