Question

please help me to solve this questions .
By making Quadratic equations​​

Answer 1

Your question in quadratic equation form

Explanation:

Let the first number be x and the second number is 27 - x.

Therefore, their product = x (27 - x)

It is given that the product of these numbers is 182.

Therefore, x(27 - x) = 182

⇒ x2 – 27x + 182 = 0

⇒ x2 – 13x - 14x + 182 = 0

⇒ x(x - 13) -14(x - 13) = 0

⇒ (x - 13)(x -14) = 0

Either x = -13 = 0 or x - 14 = 0

⇒ x = 13 or x = 14

If first number = 13, then

Other number = 27 - 13 = 14

If first number = 14, then

Other number = 27 - 14 = 13

Therefore, the numbers are 13 and 14.

Hope it will help you ♥️

Thanks

Answer 2

Answer:

let the first number be x and the second number be 27-x

Explanation:

According to Question

their product = x(27-x)

= 27x- x²= 182

= 27 x - x²- 182= 0

= - (x²+27x-182)= 0

= x²-27x+ 182=0

which is a Quadratic equation

= x²-13x-14x+182=0

= (x²-13x) (-14x+182) = 0

= x (x-13) -14 ( x-13) = 0

= ( x-14) (x-13) = 0

on finding the zeros

either ,x-14=0 ,,,.... x - 13=0

or x=14 or x= 13

Hence the two numbers are 14 and13