Question

please help me to solve this sum.​

Answer 1

Answer:

Step-by-step explanation:

ABD ≅ ACD

As shown in the figure, AB║BC

So, AB = BC

AD is the biector of BC, so it divides BC into two equal halves: - BD and DC

So, BD = DC

AD is the common side between  △ ABD and △ ADC

So, the sides of both the triangles are equal,

Therefore, it is proved that ABD ≅ ACD.

Yes, it is right to say that BD = DC because,

AD is the bisector of BC, so it divides BC into two equal halves: - BD and DC.

So, BD = DC

Answer 2

Answer:

Explanation:

Given :

• In ΔABC, AB = AC and AD is the bisector of angle A.

To Prove :

• ΔABD = ΔACD & BD = DC.

Solution :

In ΔABD & ΔACD

=> AB = AC [Given]

=> Angle BAD = Angle CAD [°.° AD is the bisector of angle A]

=> AD = AD [Common side]

=> ΔABD = ΔACD [From SAS]

=> BD = DC [CPCT]

Hence Proved!!

Know to more :

• SSS (Side-Side-Side)
• RHS (Right angle- Hypotenuse-Side)
• ASA (Angle-Side-Angle)
• AAS (Angle-Angle-Side)