Question

Please help me to solve this with working thanks!!! ​

Answer 1

Answer:

3x'2-12x+5

×'2/x3-15+5

=12'2

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Answer 2

3x^2 -12x +5=0

By completing the square you could bring the equation in the vertex form ;

Divide by 3

X^2 -4x +5/3 =0
Take the coefficient of “x” and divide by 2 , then square it . Move the constant to the RHS , and add the squared value on both the sides

X^2 -4x +4 = -5/3 + 4

(X-2)^2 = 7/3
(X-2)^2 - 7/3 = 0