Math, asked by ItzDazzingBoy, 9 months ago

please help me to solving this question​

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Answered by atulanand91
1

Answer:

a. irrational

b. rational

c. rational

d. irrational

e. irrational

Step-by-step explanation:

a. sq root 5 is an irrational no.

b. sq. root 23 can be nulified and the answer is 3 which is rational

c. sq.root 7 will be cancelled and 2/7 is left.... it is an irrational no.

d. sq. root 2 is an irrational no.

e.

\pi

is an irrational no.

hope this would help you pls mark my answer as brainliest....

Answered by 123karthikchennai
1

Step-by-step explanation:

1) First option we will do by the method we can identify that √5 is an irrational number so the first option 2-√5 is irrational

2) 3-√23-√23=3 So, it is an rational number

3) 2√7/7√7=2/7 So , it is an rational number

4) 1/√2 is an irrational number as the denominator is irrational

5) 2π is an irrational number as the value of pi has no ending decimal

Bro,Please mark me as the Brainliest Answer

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