Question

please help me today is my exam​

Answer 1

Question 7 :

Given :

• Principal = Rs.4,000
• Rate = 2% per annum
• Time = 5 years

To Find :

The Simple Interest.

Solution :

Analysis :

By using the formula for the simple interest we can find the answer.

Required Formula :

$:\normalsize\boxed{\bf Simple\ Interest=\dfrac{P\times R\times T }{100}}$

where,

• P = Principal
• R = Rate
• T = Time

Explanation :

We know that if we are given the Principal, rate and time and is asked to find the simple interest then our required formula is,

$\normalsize\boxed{\bf Simple\ Interest=\dfrac{P\times R\times T }{100}}$

where,

• P = Rs.4,000
• R = 2%
• T = 5 years

Using the required formula and substituting the required values,

$\\ :\implies\normalsize\sf Simple\ Interest=\dfrac{4000\times 2\times 5}{100}$

$\\ :\implies\normalsize\sf Simple\ Interest=\dfrac{40\cancel{00}\times 2\times 5}{1\cancel{00}}$

$\\ :\implies\normalsize\sf Simple\ Interest=\dfrac{40\times 2\times 5}{1}$

$\\ :\implies\normalsize\sf Simple\ Interest=40\times 2\times 5$

$\\ :\implies\normalsize\sf Simple\ Interest=40\times10$

$\\ \normalsize\therefore\boxed{\bf Simple\ Interest=Rs.400.}$

Simple Interest is Rs.400.

_______________________________________

Question 8 :

Given :

$\\ :\normalsize\boxed{\bf\dfrac{3x-2}{2x+1}=\dfrac{4}{5}}$

To Find :

The value of x.

Solution :

Analysis :

Here we have to evaluate as per the given information and find out the value of x.

Explanation :

$\\ :\implies\normalsize\sf\dfrac{3x-2}{2x+1}=\dfrac{4}{5}$

By cross multiplying,

$\\ :\implies\normalsize\sf5(3x-2)=4(2x+1)$

Expanding the brackets,

$\\ :\implies\normalsize\sf15x-10=8x+4$

Transposing the 8x in LHS and -10 in RHS,

$\\ :\implies\normalsize\sf15x-8x=4+10$

Adding up the numbers,

$\\ :\implies\normalsize\sf7x=14$

After Evaluation,

$\\ :\implies\normalsize\sf x=\dfrac{14}{7}$

$\\ :\implies\normalsize\sf x=\cancel{\dfrac{14}{7}}$

$\\ \normalsize\therefore\boxed{\bf x=2.}$

The value of x is 2.