Question

Please help me tommorow is my board exam

Answer 1

We know that the system of equation is:

a1x+b1y=c1 and a2x+b2y=c2

Has infinite number of solutions if:

a1\a2=b1\b2=c1c2

The given equation will have infinite number of solution

=2\a-b=3\a+b=7\3a+b-2

=2\a-b=3\a+b and 2\a-b=7\3a-b+2

=2a+2b = 3a-3b and 6a+2b-4=7a-7b

= a=5b and a-9b=-4

Putting a=5b in a-9b=-4 we will get

=5b-9b=-4

= -4b=-4

= b=1

Putting b=1 in a=5b we will get

= a=5(1)=5

Hence the given system of equations will have infinitely many solutions if:
= a=5

= b=1

Hope it will help
Thank u