please help me tomorrow is my exam
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Given the length of the courtyard = 3.78m = 378 cm.
the broad of the courtyard = 5.25m = 525cm.
GCF of 378 = 2 * 3 * 3 * 3 * 7
GCF of 525 = 3 * 5 * 5 * 7
The GCF of 378 and 525 = 3 * 7
= 21.
Therefore the largest size of the tile = 21 cm (or) 0.21m.
The number of tiles used = (378 * 525)/(21 * 21)
= 450.
Therefore the number of tiles used = 450.
Hope this helps!
the broad of the courtyard = 5.25m = 525cm.
GCF of 378 = 2 * 3 * 3 * 3 * 7
GCF of 525 = 3 * 5 * 5 * 7
The GCF of 378 and 525 = 3 * 7
= 21.
Therefore the largest size of the tile = 21 cm (or) 0.21m.
The number of tiles used = (378 * 525)/(21 * 21)
= 450.
Therefore the number of tiles used = 450.
Hope this helps!
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