Math, asked by geetikadhiman1986, 8 months ago

please help me tomorrow is my exam​

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Answered by NezamiAfshan
5

Answer:

Hope these helped ...............

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Answered by bonzotechgaming
1

We know that, (a-b) (a-b) = a² + b² - 2ab

PUTTING a AS 2x and b AS 3y

(2x-3y) (2x-3y) = (2x-3y) ²

(2x) ²+(3y) ² +2(2x×(-3y) )

= 4x² + 9y² - 6xy (ans)

(c)

We know that,

(1/a - 1/b) (1/a - 1/b) = (1/a) ² + (1/5) ² - 2/ab

PUTTING HERE a AS 1/2x and b AS 1/5y

(1/2x - 1/5y) ( 1/2x - 1/5y) = (1/2x - 1/5y) ²

(1/2x) ² + (1/5y) ² + ( 2(1/2x × (-1/5y) )

= 1/4x² + 1/25y² - 2/10xy (ans)

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