please help me tomorrow is my exam ques no 4
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ROSANNAKARYA03:
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Given: Octagon having eight equal sides, each 5 m.
Construction: Divided the octagon in 3 figures, two trapeziums whose parallel and perpendicular sides are 11 m and 4 m respectively and third figure isrectangle having length and breadth 11 m and 5 m respectively.
now,
area of a trapezium= 2×1/2(a+b)×h
=2×1/2(11+5)×4
=64m^2
And , area of rectangle=l×b
11×5=55m^2
therefore total area of octagon=64+55=119m^2
HOPE IT WILL WORK FOR YOU.....
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we can divide the figure into 2 rectangle of 4,5.. area is 20+20=40sq.m
middle rectangle area is 55sq.m
angle it have 4 triangles area=1/2*b*h
I. e, 12/2=6
6*4=24sq.m
all together the area of octagon is 40+55+24=119sq.m
middle rectangle area is 55sq.m
angle it have 4 triangles area=1/2*b*h
I. e, 12/2=6
6*4=24sq.m
all together the area of octagon is 40+55+24=119sq.m
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