Math, asked by Nafisa025, 1 year ago

please help me tomorrow is my math exam and i am so weak at math please please help me friends ans all the questions please

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Answers

Answered by simran123476
4
so our supposion is wrong so √2 is irrational
this is the answer of question 2
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Nafisa025: please ans all the questions please
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Answered by Anonymous
2

2.Given √2 is irrational number.

Let √2 = a / b wher a,b are integers b ≠ 0

we also suppose that a / b is written in the simplest form

Now √2 = a / b ⇒ 2 = a2 / b2 ⇒ 2b2 = a2

∴ 2b2 is divisible by 2

⇒ a2 is divisible by 2

⇒ a is divisible by 2

∴ let a = 2c

a2 = 4c2 ⇒ 2b2 = 4c2 ⇒ b2 = 2c2

∴ 2c2 is divisible by 2

∴ b2 is divisible by 2

∴ b is divisible by 2

∴a are b are divisible by 2 .

this contradicts our supposition that a/b is written in the simplest form

Hence our supposition is wrong

∴ √2 is irrational number.

5.


By Rationalization,


L.H.S,


×


____________________________


On Nominator,


by formula, 


On Denominator,


by formula, 

_____________________________________









_____________________________________


Then,








Now,


a =4

b√15 =√15


_______________________


a= 4 


b =1 




4.Remainder when (x + 3) divides p(x) is

= p(-3) = 3 (-3)3 - 4(-3)2 + 7 (-3) - 5

= 3 (-27) - 4 9 - 21 - 5

= -143


6.ab+ba=1⟹a2+b2−abab=0

Now back to the right hand side

a3+b3=(a+b)(a2−ab+b2)

We can notice that we have

a2+b2−abab=0⟹a2+b2−ab=0

Trivially a,b≠0 .

Thus we have

a3+b3=(a+b)(a2−ab+b2)=(a+b)⋅0=0

The result is

a3+b3=0


7.It is given that a+b = 10 and ab = 21.


Since (a+b)2 = a2 +2ab +b2,


While substituting we get


102 = a2 + 2(21)+b2.

i.e. 100 = a2 + b2 + 42,


a2+ b2= 100 -42 = 58.


Now,

a2 + b2 = (a − b)2 + 2ab


 (a − b)2  = [a2 + b2] - 2ab



 (a − b)2  = 58 - 2X21

                = 58 - 42

                =  16



10.(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)

(15)^2=83+2(ab+bc+ca)

225–83=2(ab+bc+ca)

142/2=71=ab+bc+ca

a^3+b^3+c^3–3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

=(15)(83–71)

=15×12

=180 , Answer



11.

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