Question

Please help me urrgently
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Answer 1

Step-by-step explanation:

Given:

OD is the bisector of ∠AOC

OE is the bisector of ∠BOC

OD⊥OE

Proof:

From given we have ∠AOD=∠DOC .... (1) and ∠BOE=∠EOC .... (2)

∠DOC+∠EOC=90

o

...... (a)

Substituting from 1 and 2

∠AOD+∠BOE=90

o

...... (b)

(a)+(b)

∠AOD+∠DOC+∠EOC+∠BOE=90

o

+90

o

∠AOD+∠DOC+∠EOC+∠BOE=180

o

∴ ∠AOB=180

0

and A,O and B are Collinear.

∠AOD+∠DOC=∠AOC and ∠BOE+∠EOC=∠BOC

∴ ∠AOC+∠BOC=180

o