please help me ... wid these sums
Attachments:
Answers
Answered by
0
the answer is
the base of =1/2*parllel line to the base.
x=1/2 *5
x=5/2
x=2.5
I think it would be your answet
the base of =1/2*parllel line to the base.
x=1/2 *5
x=5/2
x=2.5
I think it would be your answet
Manilachowdary1:
for 8 th question Answer is 17
thanks but which one is did??
solve it please
Answered by
0
(sol 7)given- triangle ABCsimilar triangle ADE and AD =2 db 3 nd de 5
sides of triangle abc nd ade are proportionate (given that they are similar)
so ad/ab=de/bc
ab=ad+db =2 +3 = 5 (given ad=2 db=5)
2/5=5/bc
bc=12.5
(sol 9) sin32.cos58+cos32.sin58=1
sin32.sin(90-58)+cos32.cos(90-58)
sin32.sin32+cos32.cos32
sin^2 32+cos^2 32 =1 (since sin^2theta + cos^2theta= 1)
sides of triangle abc nd ade are proportionate (given that they are similar)
so ad/ab=de/bc
ab=ad+db =2 +3 = 5 (given ad=2 db=5)
2/5=5/bc
bc=12.5
(sol 9) sin32.cos58+cos32.sin58=1
sin32.sin(90-58)+cos32.cos(90-58)
sin32.sin32+cos32.cos32
sin^2 32+cos^2 32 =1 (since sin^2theta + cos^2theta= 1)
thank u ... please help me wid other sums if i knw
Similar questions