PLEASE HELP ME!! WILL GIVE BRAINLIEST :((
Rewrite without absolute value for the given conditions:
y=|x-3|+|x+2|-|x-5|, if 3
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Modulus value means it always gives positive value.
Therefore,
if x < a, then |x - a| is positive when |x - a | = a -x, which is positive as a is larger than x.and if x >a, then |x-a| is positive when |x-a| = x - a, which is positive as a is smaller than x.
Applying the same,
(1) for -2 < x < 3,
|x - 3 | = 3 - x,
as x <3 | x + 2 | = | x - (-2)|
= x - (-2) = x+2
as x> -2 | x - 5 | = 5 -x ,
as x < 5
therefore, y = |x−3|+|x+2|−|x−5| = 3 - x + x + 2 - (5 - x) = x
- Hope it will helps ✅
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