Question

Please help me! WILL MARK BRAINLIEST! I will report absurd and incorrect answers!​

Answer 1

Answer:

radius =.3

frequency is approx 1rev/s

Explanation:

as v increase omega increase and frequency increase so there is no upper limit

Nsin37=mg

Ncos37=mv^2/r

from here r=.3

also v=rw

from here w=20/3 approx 1rev/second

Answer 2

★ QUESTION

Semi Vertical angle of the conical section of a funnel is 37 ° there is a small ball kept inside the funnel on rotating the funnel the maximum speed that the ball had can have in order to remain in the funnel is 2 m/s calculate inner radius of the brim of the funnel is there any limit upon the frequency of rotation ? how much is it ? Is it lower or upper limit ? Give the logical reason

★ ANSWER

N sin∅ = mg

and N cos∅ = $\sf \dfrac{mv ^{2} }{r}$

Therefore,

• tan∅ = $\sf \dfrac{rg }{v ^{2}}$

• r = $\sf \dfrac{v ^{2} tan∅ }{g}$

• $\sf r_{max} = \dfrac{ {v}^{2}_{max}tan ∅}{g} = 0.3m$

$\sf v = r \omega = 2\pi rn$

➠if we go for the lower limit of the speed v » 0, therefore, r » 0 , but the frequency n increases.

➠Hence a specific upper limit is not possible in the case of frequency .

➠thus, the practical limit on the frequency of rotation is its lower limit.

➠it will be possible for r = $\sf r_{max}$

$\sf r_{min} = \dfrac{v_{max}}{2\pi r_{max}}$

$\implies \sf \dfrac{1}{0.3\pi}$

$\implies \sf{ \red{ \bold{1 \: rev /s}}}$