Math, asked by manasvikadambala, 6 months ago

please help me with any of these questions answer to any question would be appreciated, and i would mark them brainliest​

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Answers

Answered by abhisheksinghr81
1

Answer:

Here, 4)=(Sin30°cos60°+Cos30°sin60°)/Tan45°cot30°-1=(Root 3-1)

1)=Here, the answer is 271/239

Step-by-step explanation:

Here, As we know that,

=Sin30°=1/2

Cos60°=1/2

Cos30°=Root3/2

Sin60°=Root3/2

Tan45°=1

Cot30°=Root3

Now, after putting the values, we get,

=[(1/2×1/2)+(Root3/2×Root3/2)/1×Root3-1

=(1/4+3/4)/Root3-1

=(1+3)/4/Root3-1

=(4/4)/Root3-1

=1/Root3-1

=Root3-1 (Answer)

1)=Here, given =15cotA=8

So, CotA=8/15

Now, As we know that,

CotA=(Base/perpendicular)=B/P

Now, construct a right -angled triangle

As we are having B and P,

So, H(Hypotenuse) would reveal out by Pythagorean theorem,

=H^2=P^2+B^2

H^2=15^2+8^2

H^2=225+64, =289

By doing square root on both sides we get,

=H=17

Now, As we know that,

SecA=H/B=17/8

CosecA=H/P=17/15

Now, by putting values of all, we get,

=(17/8+17/15-1)/(17/8-17/15+1)

=After taking out Lcm, we get,

=(225+136-120/120)/(225-136+120/120)

=(391-120/110)/(119+120/120)

=271/120/239/120

Both denominators are same(120) and divisible to each other, so they would be cancelled,

=271/239 (Answer)

I hope you would get help by these answers,

Thank you.

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